CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    The product\[(32){{(32)}^{1/6}}{{(32)}^{1/36}}.....\]to\[\infty \]is:

    A)  16         

    B)                         32

    C)  64                         

    D)         0

    E)  62

    Correct Answer: C

    Solution :

    \[(32){{(32)}^{1/6}}{{(32)}^{(1/36)}}....\] \[={{32}^{1+\frac{1}{6}+\frac{1}{36}+.....}}\] \[={{32}^{\frac{1}{1-1/6}}}={{(32)}^{6/5}}\] \[={{({{2}^{5}})}^{6/5}}={{2}^{6}}=64\]  


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