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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is:

    A)  140

    B)                                         196

    C)  280                       

    D)         346

    E)  265

    Correct Answer: B

    Solution :

    Total number of ways \[{{=}^{5}}{{C}_{4}}{{\times }^{8}}{{C}_{6}}{{+}^{5}}{{C}_{5}}{{\times }^{8}}{{C}_{5}}\]                 \[=\frac{5!}{4!\times 1!}\times \frac{8!}{2!\times 6!}+\frac{8!}{5!\times 3!}\]                 \[=\frac{5\times 8\times 7}{2}+\frac{8\times 7\times 6}{6}\] \[=140+156=196\]


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