A) 16V
B) 8V
C) 4V
D) 2V
E) zero
Correct Answer: B
Solution :
Potential on bubble, \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\] \[\therefore \] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\Rightarrow \] \[\frac{16}{{{V}^{2}}}=\frac{2}{1}\] \[\Rightarrow \] \[{{V}_{2}}=8V\]You need to login to perform this action.
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