A) 28.5 kJ
B) 17.1 kJ
C) 45.7 kJ
D) 1.7 kJ
E) 2.85 kJ
Correct Answer: C
Solution :
0.5 mol\[HN{{O}_{3}}=0.5\]mol\[{{H}^{+}}\] and\[0.3\text{ }mol\text{ }O{{H}^{-}}\] \[0.5\,{{H}^{+}}(aq)+0.3\,{{H}^{-}}(aq)\xrightarrow{{}}0.5\,{{H}_{2}}O(l)\] \[\Delta H=0.8\times 57.1\] \[=45.68\text{ }kJ\] \[=45.7\text{ }kJ\]You need to login to perform this action.
You will be redirected in
3 sec