A) \[{{R}^{2}}\]
B) \[{{R}^{-2}}\]
C) \[{{R}^{4}}\]
D) \[{{R}^{-4}}\]
E) \[{{R}^{3}}\]
Correct Answer: C
Solution :
\[F=\frac{GMM}{{{R}^{2}}}\] \[=\frac{G\left( \frac{4}{3}\pi {{R}^{3}}\rho \right)\left( \frac{4}{3}\pi {{R}^{3}}\rho \right)}{{{R}^{2}}}\] \[\therefore \] \[F\propto {{R}^{4}}\]You need to login to perform this action.
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