A) \[{{t}_{3}}=\frac{({{t}_{1}}+{{t}_{2}})}{2}\]
B) \[{{t}_{3}}=\sqrt{{{t}_{1}}{{t}_{2}}}\]
C) \[\frac{1}{{{t}_{3}}}=\frac{1}{{{t}_{1}}}-\frac{1}{{{t}_{2}}}\]
D) \[t_{3}^{2}=t_{2}^{2}-t_{1}^{2}\]
E) \[{{t}_{3}}=\frac{({{t}_{1}}-{{t}_{2}})}{2}\]
Correct Answer: B
Solution :
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