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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    Two identical solid copper spheres of radius R are placed in contact with each other. The gravitational attraction between them is proportional to:

    A)  \[{{R}^{2}}\]                                     

    B)  \[{{R}^{-2}}\]

    C)  \[{{R}^{4}}\]                     

    D)         \[{{R}^{-4}}\]

    E)  \[{{R}^{3}}\]

    Correct Answer: C

    Solution :

    \[F=\frac{GMM}{{{R}^{2}}}\] \[=\frac{G\left( \frac{4}{3}\pi {{R}^{3}}\rho  \right)\left( \frac{4}{3}\pi {{R}^{3}}\rho  \right)}{{{R}^{2}}}\] \[\therefore \]  \[F\propto {{R}^{4}}\]


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