CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    The value of\[\frac{PV}{T}\]for one mole of an ideal gas is nearly equal to:

    A)  \[2\,J\,mo{{l}^{-1}}{{K}^{-1}}\]                

    B)  \[8.3\,mo{{l}^{-1}}{{K}^{-1}}\]

    C)  \[4.2\,J\,mo{{l}^{-1}}{{K}^{-1}}\]

    D)         \[2cal\,mo{{l}^{-1}}{{K}^{-1}}\]

    E)  \[4\,cal\,mo{{l}^{-1}}{{K}^{-1}}\]

    Correct Answer: D

    Solution :

    The value of \[\frac{PV}{T}\]for one mole of an ideal gas = gas constant \[=2\,cal\,mo{{l}^{-1}}{{K}^{-1}}\]


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