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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    Two moles of\[PC{{l}_{5}}\]is heated in a closed vessel of 2L capacity. When the equilibrium is attained 40% of it has been found to be dissociated. What is the\[{{K}_{c}}\]in\[mol/d{{m}^{3}}\]?

    A) 0.532                    

    B)        0.266

    C) 0.133                    

    D)        0.174

    E) 0.25

    Correct Answer: B

    Solution :

    Number of moles of \[PC{{l}_{5}}\] dissociated at equilibrium \[=2\times 40/100=0.8\] \[\underset{2\,mol}{\mathop{PC{{l}_{5}}}}\,\underset{0}{\mathop{PC{{l}_{3}}}}\,+\underset{0}{\mathop{C{{l}_{2}}}}\,\underset{(initially)}{\mathop{{}}}\,\] (2-0.8) mol 0.8 mol 0.8 mol (at equilibrium) \[[PC{{l}_{3}}]=\frac{1.2}{2}=0.6\,M{{L}^{-1}}\]                 \[[PC{{l}_{3}}]=[C{{l}_{2}}]=\frac{0.8}{2}=0.4\,M{{L}^{-1}}\] \[\therefore \]  \[{{K}_{c}}=\frac{[PC{{l}_{3}}][C{{l}_{2}}]}{[PC{{l}_{5}}]}=\frac{0.4\times 0.4}{0.6}\] \[=0.267\text{ }mol/d{{m}^{3}}\]


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