A) 483 K, spontaneous
B) 443 K, non-spontaneous
C) 443 K, spontaneous
D) 463 K, non-spontaneous
E) 463 K, spontaneous
Correct Answer: D
Solution :
\[\Delta G=\Delta H-T\Delta S\] Where, \[\Delta H=30.558\,kJ{{K}^{-1}}\,mo{{l}^{-1}}\] \[\Delta S=0.066\,kJ{{K}^{-1}}\,mo{{l}^{-1}}\] \[\Delta G=0\] \[0=\Delta H-T\Delta S\] \[\Delta H=T\Delta S\] \[30.558=T\times 0.066\] \[T=463\,K\] Reaction is non-spontaneous reason being\[\Delta G=0\].You need to login to perform this action.
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