A) \[\pm \,3\]
B) \[\pm 6\]
C) \[-3,9\]
D) \[3,-9\]
E) 3, 9
Correct Answer: D
Solution :
Distance of a point (1, 1, 1) from\[x+y+z+k=0\]is \[\left| \frac{1+1+1+k}{\sqrt{3}} \right|\] According to question, \[\left| \frac{3+k}{\sqrt{3}} \right|=\pm 2\sqrt{3}\] \[\Rightarrow \] \[k=3,-9\]You need to login to perform this action.
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