A) 0
B) \[{{\alpha }^{6}}+{{\beta }^{6}}+{{\gamma }^{6}}+{{\delta }^{6}}\]
C) \[{{\alpha }^{6}}{{\beta }^{6}}{{\gamma }^{6}}{{\delta }^{6}}\]
D) 1
E) none of these
Correct Answer: A
Solution :
\[\because \]\[x+y+z=(\beta -\gamma )(\alpha -\delta )+(\gamma -\alpha )(\beta -\delta )\] \[+(\alpha -\beta )(\gamma -\delta )\] \[=0\] \[\therefore \]\[~{{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz=(x+y+z)\] \[({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-xy-yz-zx)\] \[=0\]You need to login to perform this action.
You will be redirected in
3 sec