A) \[C{{H}_{2}}=CHCl\]
B) \[C{{H}_{3}}CH=CHCl\]
C) \[C{{H}_{2}}=CHC(Cl)=C{{H}_{2}}\]
D) \[C{{H}_{2}}=CHC{{H}_{2}}Cl\]
E) \[{{C}_{6}}{{H}_{5}}Cl\]
Correct Answer: D
Solution :
\[C{{H}_{2}}=CH.C{{H}_{2}}Cl\]compound undergoes nucleophilic substitution most readily.
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