CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The binding energy per nucleon for deuteron and helium are 1.1 MeV and 7.0 MeV. The energy released when two deuterons ruse to form a helium nucleus is:

    A)  23.6 MeV     

    B)         2.2 MeV

    C)  30.2 MeV           

    D)         3.6 MeV

    E)  28.0 MeV

    Correct Answer: A

    Solution :

    Ratio of n/p will decrease \[{{2}_{1}}{{H}^{2}}{{\xrightarrow{{}}}_{2}}H{{e}^{4}}+Q\] Energy released \[Q=4\times 7-4\times 1.1=23.6MeV\]


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