A) \[b\text{ }tan\text{ }\alpha \text{ }cot\text{ }\beta \]
B) \[b\text{ }\cot \,\alpha \text{ tan}\,\beta \]
C) \[b\text{ cot}\,\alpha \text{ }cot\,\beta \]
D) \[b\text{ }\tan \,\alpha \text{ tan}\,\beta \]
E) \[b\text{ ta}{{\text{n}}^{2}}\,\alpha \text{ }cot\,\beta \]
Correct Answer: A
Solution :
Let CD be the tower. Then, from \[\Delta AMC\] \[\frac{b}{AC}=\tan \beta \] \[\Rightarrow \] \[AC=b\cot \beta \] From \[\Delta \Alpha DC,\frac{CD}{AC}=\tan \alpha \] \[\Rightarrow \] \[CD=b\cot \beta \tan \alpha \]You need to login to perform this action.
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