A) \[ED=EC\]
B) \[EB=EC\]
C) \[EA=ED\]
D) \[EC+ED=2BC\]
E) \[EC+ED=2DC\]
Correct Answer: E
Solution :
From figure, it is clear \[ED\ne EC\] Then \[EB\ne BC\]and \[EA\ne ED\] And \[ED>BC,\] \[EC>BC\] \[\Rightarrow \] \[EC+ED>2BC\] Hence, \[EC+ED=2DC\]You need to login to perform this action.
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