A) 2300
B) 2350
C) 2400
D) 4600
E) 4700
Correct Answer: E
Solution :
Let a and b be the first term and common difference of an AP. According to the given condition, \[a+23d=100\] ...(i) And \[{{S}_{47}}=\frac{47}{2}[2a+46d]=47[a+23d]\] \[=47\times 100=4700\] (from (i))You need to login to perform this action.
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