CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    A bag contains 3 black, 3 white and 2 red balls. One by one, three balls are drawn without replacement. The probability that the third ball is red is equal to:

    A)  \[\frac{2}{56}\]

    B)                         \[\frac{3}{56}\]

    C)  \[\frac{1}{56}\]               

    D)         \[\frac{12}{56}\]

    E)  \[\frac{14}{56}\]

    Correct Answer: E

    Solution :

     Three possible cases are \[Ist\]draw         \[IInd\]draw      \[IIIrd\]draw Red                        Non Red              Red Red                        Red                        Red Non Red              Non Red              Red \[\therefore \]Required probability \[=\frac{2}{8}\times \frac{6}{7}\times \frac{1}{6}+\frac{6}{8}\times \frac{2}{7}\times \frac{1}{6}+\frac{6}{8}\times \frac{5}{7}\times \frac{2}{6}\] \[=\frac{14}{56}\]


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