A) 7/8 kg
B) 7/5 kg
C) 8/7 kg
D) 5/7 kg
E) 7/3 kg.
Correct Answer: C
Solution :
Heat emitted by copper = Heat gained by ice \[mc\Delta \theta =mL\] \[\Rightarrow \] \[m=\frac{mc\Delta \theta }{L}\] Given, \[m=2kg,c=400J\,k{{g}^{-1}}{{C}^{-1}},\] \[\Delta \theta =500,L=3.5\times {{10}^{5}}\,J\,k{{g}^{-1}}\] \[\therefore \] \[m=\frac{2\times 400\times 500}{3.5\times {{10}^{5}}}=\frac{8}{7}kg\]You need to login to perform this action.
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