A) \[{{C}_{6}}{{H}_{6}}\]
B) \[{{C}_{4}}{{H}_{8}}\]
C) \[{{C}_{3}}{{H}_{8}}\]
D) \[C{{H}_{3}}COOH\]
E) \[C{{H}_{3}}CHO\]
Correct Answer: B
Solution :
\[Organic\text{ }compound\xrightarrow{[O]}\underset{17.6\,g}{\mathop{C{{O}_{2}}}}\,+\underset{7.2g}{\mathop{{{H}_{2}}O}}\,\] % of \[C=\frac{12}{44}\times \frac{17.6}{5.6}\times 100=85.7%\] % of \[H=\frac{2}{18}\times \frac{7.2}{5.6}\times 100=14.28%\]Element | Percentage | Relative no. of atoms | Simplest ration |
C | 85.7 | 85.7/12=7.14 | 7.14/7.14=1 |
H | 14.28 | 14.28/1 =1428 | 14.28/7.14 =2 |
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