A) \[\frac{\pi }{20}V\]
B) \[\frac{\pi }{10}V\]
C) \[20\pi \,mV\]
D) \[10\pi \,mV\]
E) \[2\pi \,mV\]
Correct Answer: C
Solution :
From Faradays law of electromagnetic induction \[e=-\frac{d\phi }{dt}=-BAN.\] Given, \[B=0.1\text{ }T,\text{ }N=20,\text{ }A=\pi {{r}^{2}}=\pi {{(0.1)}^{2}}.\] \[\therefore \] \[e=-0.1\times 20\times \pi {{(0.1)}^{2}}=20\,\pi \,mV\]
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