CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The value of\[\cos [2{{\tan }^{-1}}(-7)]\]is:

    A)  \[\frac{49}{50}\]                             

    B)         \[-\frac{49}{50}\]

    C)  \[\frac{24}{25}\]                             

    D)         \[-\frac{24}{25}\]

    E)  \[\frac{48}{49}\]

    Correct Answer: D

    Solution :

    \[\cos [2{{\tan }^{-1}}(-7)]=\cos \left[ {{\cos }^{-1}}\left( \frac{1-(49)}{1+49} \right) \right]\] \[=\cos \left[ {{\cos }^{-1}}\left( -\frac{48}{50} \right) \right]\] \[=\cos \left[ \pi -{{\cos }^{-1}}\left( \frac{48}{50} \right) \right]\] \[=-\cos {{\cos }^{-1}}\left( \frac{48}{50} \right)\] \[=-\frac{48}{50}=-\frac{24}{25}\]            


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