2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    Suppose the number of elements in set A is p, the number of elements in set B is q and the number of elements in\[A\times B\]is 7. Then \[{{p}^{2}}+{{q}^{2}}\]is equal to:

    A)  42                         

    B)         49

    C)  50                         

    D)         51

    E)  55

    Correct Answer: C

    Solution :

    \[n(A)=p,n(B)=q\]and \[n(A\times B)=7\] \[\Rightarrow \]                               \[pq=7\] \[\therefore \]Only possible values are\[p=7,q=1\] or          \[p=1,q=7\] \[\therefore \] \[{{P}^{2}}+{{q}^{2}}=49+1=50\]in either case


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