A) \[bx-ay=0\]
B) \[x+y=0\]
C) \[ax-by=0\]
D) \[x-y=0\]
E) \[ax+by=0\]
Correct Answer: D
Solution :
Point of intersection of \[\frac{x}{a}+\frac{y}{b}=1\]and\[\frac{x}{b}+\frac{y}{a}=1\]is \[\left( \frac{ab}{a+b},\frac{ab}{a+b} \right)\] \[\therefore \]Equation of line joining (0, 0) and \[\left( \frac{ab}{a+b},\frac{ab}{a+b} \right)\] is \[x=y\]i.e., \[x-y=0\]You need to login to perform this action.
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