CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    A proton, a deuteron and an alpha particle with the same kinetic energy enter a region of uniform magnetic field B at right angles to the field. The ratio of the radii of their circular paths is:

    A)  \[1:1:1\]             

    B)         \[1:\sqrt{2}:\sqrt{2}\]

    C)  \[\sqrt{2}:1:1\]                

    D)         \[\sqrt{2}:\sqrt{2}:1\]

    E)  \[1:\sqrt{2}:1\]

    Correct Answer: B

    Solution :

    Radius of circular paths is proportional to square root of mass. \[R\propto \sqrt{m}\] \[\frac{{{R}_{d}}}{{{R}_{p}}}=\sqrt{\frac{{{m}_{d}}}{{{m}_{p}}}}=\frac{\sqrt{2}}{1}\] \[\Rightarrow \]               \[\frac{{{R}_{p}}}{{{R}_{d}}}=\frac{1}{\sqrt{2}}\] Also, \[\frac{{{R}_{d}}}{{{R}_{\alpha }}}=\frac{\sqrt{{{M}_{d}}}}{\sqrt{{{M}_{\alpha }}}}=\frac{\sqrt{2}}{\sqrt{4}}=\frac{1}{\sqrt{2}}\] Hence, ratio is\[1:\sqrt{2}:\sqrt{2}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner