A) \[\frac{{{a}^{2}}}{{{b}^{2}}}\]
B) \[\frac{a}{b}\]
C) \[\frac{b}{a}\]
D) \[\frac{{{a}^{2}}+{{b}^{2}}}{{{a}^{2}}-{{b}^{2}}}\]
E) \[\frac{{{a}^{2}}-{{b}^{2}}}{{{a}^{2}}+{{b}^{2}}}\]
Correct Answer: B
Solution :
\[\frac{\sin (x+y)}{\sin (x-y)}=\frac{a+b}{a-b}\] \[\Rightarrow \] \[\frac{\sin (x+y)+\sin (x-y)}{\sin (x+y)-\sin (x-y)}=\frac{(a+b)+(a-b)}{(a+b)-(a-b)}\] \[\Rightarrow \] \[\frac{2\sin x\cos y}{2\cos x\sin y}=\frac{2a}{2b}\] \[\Rightarrow \] \[\frac{\sin x\cos y}{\cos x\sin y}=\frac{a}{b}\] \[\Rightarrow \] \[\frac{\tan x}{\tan y}=\frac{a}{b}\]
You need to login to perform this action.
You will be redirected in
3 sec
