A) \[x+2y+3z-6=0\]
B) \[x+2y+3z-1=0\]
C) \[x+2y+3z-8=0\]
D) \[x+2y+\text{ }3z-3=0\]
E) \[x+2y+3z-10=0\]
Correct Answer: A
Solution :
All the given planes are parallel to each other but only\[x+2y+3z-6=0\]is equidistant from \[x+2y+3z-5=0\] and \[x+2y+3z-7=0\]having distance\[\frac{1}{\sqrt{14}}\].You need to login to perform this action.
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