A) \[7x-y-6=0\]
B) \[x-2y+1=0\]
C) \[3x-2y-1=0\]
D) \[x-7y+6=0\]
E) \[2x-3y+1=0\]
Correct Answer: B
Solution :
Let the another equation of line is \[x-2y+1=0.\] \[\therefore \]Equation of bisecting the lines between two lines is \[\frac{2x-y-1}{\sqrt{4+1}}=\pm \frac{x+2y+1}{\sqrt{1+4}}\] \[\Rightarrow \] \[2x-y-1=\pm x-2y+1\] \[\Rightarrow \] \[x+y-2=0\] and \[x=y\]
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