A) \[\frac{1}{2}sq\,unit\]
B) \[\frac{1}{4}sq\,unit\]
C) \[1sq\,unit\]
D) \[2\,sq\,unit\]
E) 4 sq unit
Correct Answer: B
Solution :
The vertices of a triangle are \[(0,2),\left( \frac{1}{2},1 \right),(1,1)\] \[\therefore \]Area of triangle\[=\frac{1}{2}\left| \begin{matrix} 0 & 2 & 1 \\ \frac{1}{2} & 1 & 1 \\ 1 & 1 & 1 \\ \end{matrix} \right|\] \[=\frac{1}{2}\left[ -2\left( \frac{1}{2}-1 \right)+1\left( \frac{1}{2}-1 \right) \right]=\frac{1}{4}sq\,unit\]
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