question_answer

A toy cyclist completes one round of a square track of side 2 m in 40s. What will be the displacement at the end of 3 min?

A)  52 m                    

B)         Zero

C)  16m                     

D)         \[2\sqrt{2}m\]

E)  \[4\sqrt{2}m\]

Correct Answer: D

Solution :

Displacement is distance from initial to final position. In \[40\text{ }s1\] round In \[3\times 60=180\text{ }s4\frac{1}{2}\]round Displacement for 4 rounds is zero. For\[\frac{l}{2}\]round, length of diagonal\[=2\sqrt{2}m\].