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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    If the plane\[2x-y+z=0\]is parallel to the line \[\frac{2x-1}{2}=\frac{2-y}{2}=\frac{z+1}{a},\]then the value of a is:

    A)  4                            

    B)         \[-4\]

    C)  2                            

    D)         \[-2\]

    E)  0

    Correct Answer: B

    Solution :

    Line is parallel to the given plane i.e., \[\frac{x-\frac{1}{2}}{1}=\frac{y-2}{-2}=\frac{z+1}{a}\]is parallel to \[2x-y+z=0\] If            \[2+2+a=0\] \[\Rightarrow \]               \[a=-4\]


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