CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v, then the escape velocity from the planet is:

    A)  \[\sqrt{3}v\]                     

    B)         \[\sqrt{2}v\]

    C)  \[v\]                    

    D)         \[\sqrt{5}v\]

    E)  \[\sqrt{12}v\]

    Correct Answer: A

    Solution :

    Escape velocity, \[{{v}_{e}}=\sqrt{\frac{2G{{M}_{e}}}{{{R}_{e}}}}\] Given,      \[{{M}_{p}}=6{{M}_{e}},{{R}_{p}}=2{{R}_{e}}\] \[\therefore \]  \[{{v}_{p}}=\sqrt{\frac{2G\,6{{M}_{e}}}{(2{{R}_{e}})}}=\sqrt{3}{{v}_{e}}\]


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