question_answer

The inputs and outputs for different time intervals are given below the NAND gate

Time	Input A	Input B	Output Y
\[{{t}_{1}}\,to\,{{t}_{2}}\]	0	1	P
\[{{t}_{2}}\,to\,{{t}_{3}}\]	0	0	Q
\[{{t}_{3}}\,to\,{{t}_{4}}\]	1	0	R
\[{{t}_{4}}\,to\,{{t}_{5}}\]	1	1	S

The values taken by P, Q, R, S are respectively:

A)  1, 1, 1, 0        

B)         0, 1, 0, 1

C)  0, 1, 0, 0        

D)         1, 0, 1, 1

E)  1, 0, 1, 0

Correct Answer: A

Solution :

NAND gate is obtained when the output of AND gate is made as the input of NOT gate Boolean expression for NAND gate is: \[Y=\overline{A.B}\]

A	B	Y
0	0	1
1	0	1
0	1	1
1	1	0