(i) chloroethene |
(ii) benzene |
(iii) 1, 3-butadiene |
(iv) 1, 3, 5-hexatriene |
A) (i), (iii), (iv) only
B) (i), (ii) only
C) (ii), (iii), (iv) only
D) (iii), (iv) only
E) (i), (ii), (iii) and (iv)
Correct Answer: E
Solution :
\[\underset{chloroethene}{\mathop{\underset{s{{p}^{2}}}{\mathop{ClCH}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,,}}\,\] all carbon atoms are \[s{{p}^{2}}\]hybridized \[\underset{1,\text{ }3-butadiene}{\mathop{\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{CH_{2}^{}}}\,}}\,\] \[\underset{1,3,\text{ }5-hexatriene}{\mathop{\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,}}\,\]You need to login to perform this action.
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