A) \[20.7\times {{10}^{-17}}N/{{m}^{2}}\]
B) \[15.3\times {{10}^{-15}}N/{{m}^{2}}\]
C) \[2.3\times {{10}^{-10}}N/{{m}^{2}}\]
D) \[5.3\times {{10}^{-5}}N/{{m}^{2}}\]
E) \[3.5\times {{10}^{-8}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
From ideal gas equation \[PV=nkT\] \[P=\frac{n}{V}kT\] Here, \[\frac{n}{V}=5/c{{m}^{3}}=5\times {{10}^{6}}/{{m}^{3}}\] \[\therefore \]\[P=(5\times {{10}^{6}}/{{m}^{3}})(1.38\times {{10}^{-23}}J/K)\times 3K\] \[P=20.7\times {{10}^{-17}}N/{{m}^{2}}\]You need to login to perform this action.
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