CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The apparent frequency of the whistle of an engine changes in the ratio\[9:8\]as the engine passes a stationary observer. If the velocity of the sound is\[340\text{ }m{{s}^{-1}},\]then the velocity of the engine is:

    A)  \[40\text{ }m{{s}^{-1}}\]             

    B)         \[20\text{ }m{{s}^{-1}}\]

    C)  \[340\text{ }m{{s}^{-1}}\]      

    D)         \[\text{180 }m{{s}^{-1}}\]

    E)  \[50\text{ }m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    From Dopplers effect, perceived frequency \[f=f\left( \frac{v-{{v}_{o}}}{v-{{v}_{s}}} \right)\] \[\frac{9}{8}=\frac{340}{340-{{v}_{s}}}\] \[\Rightarrow \] \[9(340-{{v}_{s}})=8\times 340\] \[\Rightarrow \] \[{{v}_{s}}=37.7\,m{{s}^{-1}}\approx 40\,m{{s}^{-1}}\]


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