A) 0.2mm
B) \[2\times {{10}^{-5}}mm\]
C) \[2\times {{10}^{5}}mm\]
D) 2 mm
E) 0.02mm
Correct Answer: B
Solution :
The angular distance \[(\theta )\] is given by \[\theta =\frac{\lambda }{d}\] \[\theta ={{2}^{{}^\circ }}=\frac{\pi }{180}\times 2,\lambda =6980\overset{\text{o}}{\mathop{\text{A}}}\,\] \[=6980\times {{10}^{-10}}m\] \[\Rightarrow \] \[d=\frac{\lambda }{\theta }=\frac{6980\times {{10}^{-10}}\times 180}{3.14\times 2}\] \[1.89\times {{10}^{-5}}mm\] \[\Rightarrow \] \[d=2\times {{10}^{-5}}mm\]
You need to login to perform this action.
You will be redirected in
3 sec
