CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    In a certain region of space there are only molecules per cm3 on an average. The temperature there is 3 K. The pressure of this dilute gas is: \[(k=1.38\times {{10}^{-~23}}J/K)\]

    A)  \[20.7\times {{10}^{-17}}N/{{m}^{2}}\]

    B)  \[15.3\times {{10}^{-15}}N/{{m}^{2}}\]

    C)  \[2.3\times {{10}^{-10}}N/{{m}^{2}}\]

    D)  \[5.3\times {{10}^{-5}}N/{{m}^{2}}\]

    E)  \[3.5\times {{10}^{-8}}N/{{m}^{2}}\]

    Correct Answer: A

    Solution :

    From ideal gas equation \[PV=nkT\] \[P=\frac{n}{V}kT\] Here, \[\frac{n}{V}=5/c{{m}^{3}}=5\times {{10}^{6}}/{{m}^{3}}\] \[\therefore \]\[P=(5\times {{10}^{6}}/{{m}^{3}})(1.38\times {{10}^{-23}}J/K)\times 3K\] \[P=20.7\times {{10}^{-17}}N/{{m}^{2}}\]


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