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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    A symmetrical body is rotating about its axis of symmetry, its moment of inertia about the axis of rotation being\[1\text{ }kg{{m}^{2}}\]and its rate of rotation 2 rev/s. The angular momentum is:

    A)  \[1.257\,kg\,{{m}^{2}}/s\]  

    B)         \[12.57\,kg\,{{m}^{2}}/s\]

    C)  \[13.57\,kg\,{{m}^{2}}/s\]  

    D)         \[20\,kg\,{{m}^{2}}/s\]

    E)  \[1.357\,kg\,{{m}^{2}}/s\]

    Correct Answer: B

    Solution :

    Given, \[I=1kg{{m}^{2}},n=2\,rps\] \[\omega =2\pi n=2\pi \times 2=4\pi \,rad/s\]                 \[L=I\omega =1(4\pi )=12.57\,kg\,{{m}^{2}}/s\]


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