CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The momentum of a body is increased by 25%. The kinetic energy is increased by about:

    A)  25%                      

    B)         5%

    C)  56%                      

    D)         38%

    E)  65%

    Correct Answer: C

    Solution :

    The relation between K and p is \[P=\sqrt{2K}m\] when increased by 25%, we have                 \[P=P+\frac{25}{100}P=\frac{5P}{4}\] \[\Rightarrow \]               \[\frac{4p}{5p}=\frac{{{K}_{1}}}{{{k}_{2}}}\] \[\Rightarrow \]               \[\frac{{{K}_{1}}}{{{k}_{2}}}=\frac{16}{25}\] Hence, percentage increase is \[=\frac{25-16}{16}\times 100=\frac{9}{16}\times 100=56.25%\]


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