A) 1 mg
B) 2 mg
C) 3 mg
D) 4 mg
E) 7mg
Correct Answer: A
Solution :
From Rutherford-Soddy law \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[n=\frac{38}{3.8}=10\] The initial quantity of radon is\[{{N}_{0}}=1024\text{ }mg\]. Therefore, the mass of radon left after 10 half-lives is \[N=1024\times {{\left( \frac{1}{2} \right)}^{10}}=\frac{1024}{1024}=1\,mg\]
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