A) \[31%\text{ }M{{g}^{+}}+69%\text{ }M{{g}^{2+}}\]
B) \[69%\text{ }M{{g}^{+}}+31%\text{ }M{{g}^{2+}}\]
C) \[86%\text{ }M{{g}^{+}}+14%\text{ }M{{g}^{2+}}\]
D) \[14%\text{ }M{{g}^{+}}+86%\text{ }M{{g}^{2+}}\]
E) \[13%\text{ }M{{g}^{+}}+87%\text{ }M{{g}^{2+}}\]
Correct Answer: B
Solution :
\[Mg\xrightarrow[{}]{{}}M{{g}^{+}},\] \[E=750\,kJ\] Remaining energy\[=1200-750=450\text{ }kJ\] Energy needed to convert 1 mol of\[M{{g}^{+}}\]to \[M{{g}^{2+}}=1450\] Number of moles of\[M{{g}^{2+}}\]produced \[=\frac{1}{1450}\times 450\] \[=0.31\] \[=31%\] Number of moles of\[M{{g}^{+}}\]produced\[=1-0.31\] \[=0.69\] \[=69%\]
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