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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    At certain temperature a 5.12% solution of cane sugar is isotonic with a 0.9% solution of an unknown solute. The molar mass of solute is:

    A) 60                          

    B)        46.17

    C) 120                        

    D)        90

    E) 92.34

    Correct Answer: A

    Solution :

    Solutions having same osmotic pressure are called isotonic solutions. The osmotic pressure is given as: \[\because \]     \[\pi =\frac{{{w}_{B}}RT}{V{{M}_{B}}}\] \[\pi \](cane sugar) = \[\pi \] (unknown solute)                 \[\frac{5.12}{3.42}=\frac{0.9}{M}\]                 \[M=\frac{342\times 0.9}{5.12}\]                 \[=60\]


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