CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    Number of integral solutions of\[\frac{x+2}{{{x}^{2}}+1}>\frac{1}{2}\]is

    A)  0                                            

    B)  1

    C)  2                            

    D)         3

    E)  4

    Correct Answer: D

    Solution :

    Given that, \[\frac{x+2}{{{x}^{2}}+1}>\frac{1}{2}\] \[\Rightarrow \]               \[2x+4>{{x}^{2}}+1\] \[\Rightarrow \]               \[{{x}^{2}}-2x-3<0\] \[\Rightarrow \]               \[(x-3)(x+1)<0\] \[\Rightarrow \]               \[-1<x<3\] The value of x are 0, 1, 2. \[\therefore \]The number of integral solutions is 3.


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