CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    A conducting rod of 1 m length and 1 kg mass is suspended by two vertical wires through its ends. An external magnetic field of 2 T is applied normal to the rod. Now the current to be passed through the rod so as to make the tension in the wires zero is [Take\[g=10\text{ }m{{s}^{-2}}\]]

    A)  0.5 A                                    

    B)  15 A                     

    C)  5 A                        

    D)         1.5 A

    E)  2.5 A

    Correct Answer: C

    Solution :

    Magnetic force on the rod \[=BIl\] Weight of the rod\[=mg\] For no tension in wire, \[BIl=mg\] Or           \[I=\frac{mg}{Bl}=\frac{1\times 10}{2\times 1}=5A\]


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