A) \[xyz\]
B) \[2xyz\]
C) \[xy{{z}^{2}}\]
D) \[{{x}^{2}}yz\]
E) \[3xyz\]
Correct Answer: A
Solution :
\[{{\sec }^{-1}}\sqrt{1+{{x}^{2}}}+\cos e{{c}^{-1}}\frac{\sqrt{1+{{y}^{2}}}}{y}\] \[+{{\cot }^{-1}}\frac{1}{z}=\pi \] \[\Rightarrow \] \[{{\tan }^{-1}}x+{{\tan }^{-1}}y+{{\tan }^{-1}}z=\pi \] \[\Rightarrow \] \[{{\tan }^{-1}}\left( \frac{x+y+z-xyz}{1-xy-yz-zx} \right)=\pi \] \[\Rightarrow \] \[x+y+z=xyz\]
You need to login to perform this action.
You will be redirected in
3 sec
