A) 1
B) 2
C) 0
D) 1/2
E) \[-2\]
Correct Answer: C
Solution :
\[\because \]\[f(x)=2{{x}^{2}}+bx+c\] and\[f(0)=3\]and\[f(2)=1\] \[\therefore \]\[c=3\]and\[8+2b+c=1\] \[\Rightarrow \]\[8+2b+3=1\Rightarrow b=-5\] \[\therefore \] \[f(x)=2{{x}^{2}}-5x+3\] \[\Rightarrow \]\[f(1)=2{{(1)}^{2}}-5(1)+3\] \[=2-5+3=0\]You need to login to perform this action.
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