A) 4
B) \[-\,4\]
C) 7
D) \[-\text{ }7\]
E) 3
Correct Answer: D
Solution :
\[\because \] \[z=\frac{11-3i}{1+i}\times \frac{1-i}{1-i}\] \[=\frac{11-11i-3i-3}{1+1}\] \[=\frac{8-14i}{2}=4-7i\] Also, \[\alpha \]is a real number such that\[z-i\alpha \]is real. \[\therefore \]\[4-7i-i\alpha \] is real, if \[\alpha =-7\].You need to login to perform this action.
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