CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    A paramagnetic substance of susceptibility \[3\times {{10}^{-4}}\]is placed in a magnetic field of\[4\times {{10}^{-4}}A{{m}^{-1}}\]. Then the intensity of .magnetization in the units of\[A{{m}^{-1}}\]is

    A)  \[1.33\times {{10}^{8}}\]                            

    B) \[0.75\times {{10}^{-8}}\]            

    C)         \[12\times {{10}^{-8}}\]              

    D)         \[14\times {{10}^{-8}}\]

    E)  \[1.2\times {{10}^{-8}}\]

    Correct Answer: C

    Solution :

    Susceptibility \[(\chi )\] \[=\frac{intensity\text{ }of\text{ }magnetisation(I)}{magnetic\text{ }field(B)}\] or       \[I=\chi B\] \[\therefore \]  \[I=3\times {{10}^{-4}}\times 4\times {{10}^{-4}}\] or            \[I=12\times {{10}^{-8}}A{{m}^{-1}}\]


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