A) \[2.5\times {{10}^{-5}}\]
B) \[4\times {{10}^{-12}}\]
C) \[2.5\times {{11}^{11}}\]
D) \[2\times {{10}^{6}}\]
E) \[5\times {{10}^{5}}\]
Correct Answer: C
Solution :
\[2N{{O}_{2}}(g)2NO(g)+{{O}_{2}}(g)\] \[K=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}=2\times {{10}^{-6}}\] \[4N{{O}_{2}}(g)+2{{O}_{2}}(g)4N{{O}_{2}}(g)\] \[K=\frac{{{[N{{O}_{2}}]}^{4}}}{{{[NO]}^{4}}{{[{{O}_{2}}]}^{2}}}\] \[=\frac{1}{{{(K)}^{2}}}=\frac{1}{{{(2\times {{10}^{-6}})}^{2}}}\] Equilibrium constant\[K=0.25\times {{10}^{12}}\] \[=2.5\times {{10}^{11}}\]You need to login to perform this action.
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